Question 395752
We have


{{{(sqrt(3)8h^(-2)s^(-4))/(sqrt(3)h^(-6)s^4)}}}


Cancelling out {{{sqrt(3)}}} and simplifying the exponents we obtain


{{{8h^4s^(-8)}}} which implies k = 8, r= 4, t = -8.


Btw algebra.com doesn't parse LaTeX code...I really wish it did though, since it's a much better way to input math expressions.