Question 395573
if you are given

{{{f(x)=(x+3)/(x+1)}}}, {{{(f(x)-f(1))/(x-1)}}}

and if you need to find

{{{(f(x)-f(1))/(x-1)}}}

then first find 

{{{f(1)}}}.....where {{{x=1}}

{{{f(1)=(1+3)/(1+1)}}}

{{{f(1)=4/2}}}


{{{f(1)= 2}}}.....now plug it in


{{{(f(x)-f(1))/(x-1)}}}


{{{(((x+3)/(x+1)) - 2)/(x-1)}}}


{{{(((x+3-2(x+1))/(x+1)))/(x-1))}}}


{{{(((x+3-2x-2))/(x+1)))/(x-1))}}}



{{{(((-x+1))/(x+1)(x-1)))}}}


{{{(-(cross((x-1)))/(x+1)cross((x-1))))}}}



{{{-1/(x+1)}}}