Question 395669
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Let *[tex \Large t] represent the time running at 8 mph.  Then, since the total time was 4 hours, the time spent bicycling must have been *[tex \Large 4\ -\ t]


Running rate times running time plus bicycling rate times bicycling time is equal to running distance plus bicycling distance is equal to total distance, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8t\ +\ 20(4\ -\ t)\ =\ 62]


Solve for *[tex \Large t] and *[tex \Large 4\ -\ t]


Once you have the times for each leg, the distances follow directly.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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