Question 395661
Find an nth degree polynomial function with real coefficients satifying the given conditions:

n=3; 4 and 2i are zeros;
Complex solutions occur in conjugate pairs, so -2i is also a zero.

f(n) = (n-3)(n-4)(n-2i)(n+2i)
{{{f(n) = (n^2-7n+12)*(n^2 + 4)}}}
Multiply those, that's the function.
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f(-1) = 100
Multiply by -1/2
{{{f(n) = (-1/2)*(n^2-7n+12)*(n^2 + 4)}}}
f(-1)=-50