Question 395628
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Hi
-x+2y=8
 x-2y=8  |solving by first eliminating y (adding the two equatons)
  0 &#8800; 16  There is NO solution to this system

x-2y=-4
-x+2y=4  |solving by first eliminating y (adding the two equatons)
  0 = 0  these are the same lines, infinite points in common for this system