Question 395560
<pre><font size = 3 color = "indigo"><b>
Hi
f(x)= -(x+9)^2-4
Finding vertex
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x)= -(x+9)^2-4  | Vertex is Pt(-9,-4) Line of symmetry is x= -9
 -1 = a < 0, parabola opens downward f(-9) = -4 is a maximum point for f(x) 

{{{drawing(300,300, -15,15,-15,15 ,blue(line(-9,15,-9,-15))   grid(1),
circle(-9, -4,0.5),
graph( 300, 300, -15,15,-15,15, -(x+9)^2-4
))}}}