<PRE><B>Question 395429</B>
When the area of a rectangle is 3 times the length and the lenght is 1 more than twice the width, what are the demensions?

I know somthing is missing in my formula.  Please help?  Thanks.
A = L*W

W = x 
L = 2x + 1

x(2x + 1) = 3(2x + 1)

2x^2 + x = 6x + 3
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You missed the signs at this point:

2x^2 - 5x - 3 = 0

2x^2 -6x+x -3 = 0
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2x(x-3)+(x-3) = 0
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(x-3)(2x+1) = 0
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Positive solution:
x = 3 (width)
2x+1 = 7 (length)
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Cheers,
Stan H.
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