Question 43034
 
    {{{2x^3-26^2+80x}}}

=  {{{2x(x^2-13x+40)}}}
 
=  {{{2x(x^2-5x-8x+40)}}}
 
=  {{{2x*(x(x-5)-8(x-5))}}}
 
=  {{{2x*(x-5)*(x-8)}}}  Answer.  First of all factorise the expression by the common factor i.e. 2x.  Then factorise x^2-13x+40 into (x-5)(x-8).  As these factors cannot be further factorised, 2x*(x-5)(x-8) is the Answer.  I hope this is clear to you.  



gsm