Question 395358
Recall that cot(x)=1/tan(x) and that tan(x)=sin(x)/cos(x)



So this means that cot(x)=cos(x)/sin(x)



So 


sin(x)+cot(x)cos(x) = sin(x)+(cos(x)/sin(x))cos(x)


sin(x)+cot(x)cos(x) = sin(x)+cos^2(x)/sin(x)


sin(x)+cot(x)cos(x) = sin^2(x)/sin(x)+cos^2(x)/sin(x)


sin(x)+cot(x)cos(x) = (sin^2(x)+cos^2(x))/sin(x)


sin(x)+cot(x)cos(x) = 1/sin(x)



So the answer is choice G



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Jim