Question 395306
  <pre><font size = 3 color = "indigo"><b>
Hi
f(x)=3x^2-6x-2
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x)=3[(x-1)^2 -1]-2   |completing the square to put into vertex form
f(x)=3(x-1)^2 -5  Vertex is Pt(1,-5)
a = 3 >0 parabola opens upward  Pt(1,-5) a minimum point
 domain is all real numbers, range is all real numbers &#8805; -5
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(1, -5,0.3),
graph( 300, 300, -6, 6, -6, 6,3x^2-6x-2
))}}}