Question 395287
You need to put the formula in standard form  y=a(x-h)^2+k 
(h,k) is the vertex
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you have three points.  the origion  (0,0) the end (32,0) and its middle (16,14) which is the vertex
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let's use input the vertex in the standard formula
y=a(x-16)^2+14
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lets use the origin (0,0) to solve for "a"
0=a(-16)^2+14
0=256a+14
a=-14/256= - 7/128
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substitute a into formula
y=-7/128*(x-16)^2+14