Question 5451
Start by multiplying both sides by the denominator which is 3:

{{{y+4=(-2/3)*(x-9)}}}
{{{3*(y+4)=3*(-2/3)*(x-9)}}}
{{{3y + 12 = -2(x-9)}}}
{{{3y + 12 = -2x + 18}}}


Add +2x and - 12 to each side:
{{{2x + 3y + 12 - 12 = -2x + 2x + 18 - 12}}}

{{{2x + 3y = 6}}}


R^2 at SCC