Question 395184
graph the inequality on a plane

3x+4y<12
add -3x to both sides
4y<-3x+12
/4
y<-3x/4 +3
..
find the boundary for the equation by the equation y = -3x/4+3
x=0y=3..... (0,3)
y=0,x=4....(4,0)
locate the ontercepts and draw the line.
...
the boundary

{{{drawing(300,300,-5,5,-5,5,circle(0,3,0.2),circle(4,0,0.2),graph(300,300,-5,5,-5,5,y=(-3x/4)+3))}}}

The inequality
{{{graph(300,300,-5,5,-5,5,y<(-3x/4)+3)}}}

m.ananth@hotmail.ca