Question 395018
{{{2sqrt(x+4)-1/2=x}}}
{{{sqrt(x+4)-1/2=x/2}}}
{{{sqrt(x+4)=x/2+1/2}}}
{{{x+4=(x/2+1/2)^2}}}
{{{x+4=x^2/4+x/2+1/4}}}
{{{x^2/4+x/2-15/4=0}}}
From here, the easiest method would be to use the quadratic equation:
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
Your formula, {{{x^2/4+x/2-15/4}}} is in the form ax^2+bx+c.
So, a, b, and c are:
{{{a=1/4}}}
{{{b=1/2}}}
{{{c=-15/4}}}
From here, you just plug in a, b, and c into the quadratic formula.

I'll leave the rest to you.

Hope this helps,
J