Question 395017
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Hi, Note correction of middle term of trinomial**
solving
{{{ sqrt(2x)= x-4 }}}   |squaring both sides
  2x = (x-4)^2
  2x = x^2 - 8x + 16
  x^2 -10x + 16 = 0    |**
factoring
(x-8)(x-2) = 0
(x-8)= 0  x = 8
(x-2) = 0 x = 2  Extraneous solution
 x = 8