Question 394981
  <pre><font size = 3 color = "indigo"><b>
Hi
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
{{{f(x)=2(x-3)^2}}}  Vertex is Pt(3,0) and x = 3 the line of symmetry
{{{drawing(300,300, -6, 6, -6, 6,blue(line(3,6,3,-6)),    grid(1),
circle(3, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,2(x-3)^2))}}}