Question 394948
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Hi
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius
1.)Center Pt(0,0) and r = 6    x^2 + y^2 = 36
2.)Center Pt(-2,4)and r = 4    (x+2)^2 + (y-4)^2 = 16