Question 394940
Let x = the increase in the number of feet for the width and for the length.
The new area will be:
{{{(15+x)(20+x) = 900}}} Simplify.
{{{300+35x+x^2 = 900}}} Rewrite in standard quadratic form.
{{{x^2+35x-600 = 0}}} Solve using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{x = (-35+-sqrt(35^2-4(1)(-600)))/2}}}
{{{x = (-35+-sqrt(1225-(-2400)))/2}}}
{{{x = (-35+-sqrt(3625))/2}}}
{{{x[1] = -47.6}}} or {{{x = 12.6}}} Discard the negative solution as width/length are positive values.
The length and the width must be increased by 12.6 feet each.