Question 394852
 t^2+6t/t^2+3t-18 divided by t/t3 (I assume that this means t/t^3=1/t^2)
t(t+6)/(t+6)(t-3)=t/(t-3)
t/(t-3) / t/t^3
= t/(t-3) * t^2
= t^3/(t-3)
.
Ed