<PRE><B>Question 394530</B>
A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid
 ounces of 25% alcohol solution.
 How many fluid ounces of each are needed?
:
Let x = amt of 35% solution
then
(60-x) = amt of 20% solution
:
A typical mixture equation based on percent alcohol
.35x + .20(60-x) = .25(60)
.35x + 12 - .20x = 15
.35x - .20x = 15 - 12
.15x = 3
x = {{{3/.15}}}
x = 20 0z of 35% solution required
then
60 - 20 = 40 oz of 20% solution required
:
:
Check 
.35(20) + .20(60-20) = .25(60)
7 + 8 = 15</PRE>