Question 394323
log(x+3)+log(x-2)= log14
use logarithm rule for multiplication
log(x+3)(x-2) =log14
(x+3)(x-2)=14
 x^2+x-6=14
 x^2+x-20=0
solve by factoring
(x+5)(x-4)=0
ans: x=-5(reject,logarithm>0)
     x=4
check:
log(x+3)+log(x-2)= log14
log7+log2=log14
.8451+.3010=1.146
      1.146=1.146