Question 394823
Question: 
Find the derivative of y in the following when x=1
xy^3 + x^2 = 2 
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x(3y^2*y')+2x = 0
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y' = -2x/3xy^2
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y' = -2/3y^2
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The derivative does not depend on the value of "x".
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Cheers,
Stan H.