Question 394799
Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic fuction, and graph the function.  
f(x)=3x^2-12x+16
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Vertex occurs at x = -b/(2a) = 12/(6) = 2
f(2) = 3*2^2-12*2+16 = 12-24+16 = 4

The vertex is (2,4) (Type an ordered pair.)

The line of symmetry is x=2
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A. y=4
B. x=2
C. x=-2
D. y=-4

The maximum/minimum of f(x) is (2,4).

Is the value, f(2)=4 a minimum or a maximum?
Minimum
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Graph.
{{{graph(400,300,-10,10,-10,20,3x^2-12x+16)}}}
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Cheers,
Stan H.