Question 394798


{{{(x-2)^2=12}}}

{{{x^2 - 4x + 4 =12}}}

{{{x^2 - 4x + 4 - 12 = 0}}}

{{{x^2 - 4x - 8 = 0}}}

*[invoke quadratic_formula 1, -4, -8, "x"]


 the exact solutions are

{{{x1 = 2 + 2sqrt(3) = 2+2*1.73 = 2 + 3.46 = 5.46 }}}


{{{x2 = 2 - 2sqrt(3) = 2-2*1.73 = 2 - 3.46 = -1.46 }}}


the approximate solutions


{{{x1 = 2 + 2sqrt(3) = 5.46 = 6}}}

{{{x2 = 2 - 2sqrt(3) = -1.46 = -2 }}}