<PRE><B>Question 394796</B>
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Let *[tex \Large w] represent the width.  Then the length is *[tex \Large 2w\ +\ 3].  The perimeter is 2 times the length plus 2 times the width.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(w)\ =\ 2(2w\ +\ 3)\ +\ 2w]


You will need to simplify and collect terms to finish the problem.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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