Question 394743
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Hi
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = –2x^2-4x+3         |completing square to put into vertex form
y = –2[x+1)^2 -1]+3 
y = –2(x+1)^2 +5  Vertex Pt(-1,5)  Axis of symmetry is x = -1
{{{drawing(300,300, -6, 6, -6, 6, blue(line(-1,6,-1,-6)),   grid(1),
circle(-1, 5,0.3),
graph( 300, 300, -6, 6, -6, 6,-2x^2-4x+3))}}}