Question 394691
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Hi
Note: vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
{{{f(x)=2x^2-8x+8}}}    |completing square to put into vertex form
{{{f(x)=2(x-2)^2}}}  Vertex pt(2,0), a minimum point for F(x)
Line of symmetry is x = 2
 {{{drawing(300,300, -6, 6, -6, 6,blue(line(2,6,2,-6)),   grid(1),
circle(2, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,2x^2-8x+8 ))}}}