Question 394614
I need the last two digits from the following numbers 11^2011.
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The last 2 digits are cyclic, and are equal to the exponent modulo 10.
For exponents from 1 to 10, they are:
11
21
31
41
51
61
71
81
91
01
Then they repeat.
2011/10 = 201 remainder 1, so the last 2 digits are the same as 11^1
= 11.