Question 394670
{{{8^(2n+1)= 2^(n+18)}}} ;n= 
:
Since 8 can be written 2^3, we can write the equation
{{{2^(3(2n+1))= 2^(n+18)}}}
which is:
{{{2^(6n+3)= 2^(n+18)}}}
now since they have the same base we can ignore the base and write it
6n + 3 = n + 18
6n - n = 18 - 3
5n = 15
n = 15/5
n = 3
:
:
Check this in the original problem
{{{8^(2(3)+1)= 2^(3+18)}}}
{{{8^7= 2^21}}}
a calc gives 2097152 for both sides