<PRE><B>Question 394631</B>
Let x=1/6 and y=5/6
(x+y)^4=x^4+4x^3y+6x^2y^2+4xy^3+y^4
P(exacty one 3)
4xy^3=.3858
.
P(exacty three 3s)
4x^3y=.0154
.
P(at most two 3s)
y^4+4xy^3+6x^2y^2=.9838
.
Ed
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