Question 394465
{{{x^2+4x>12}}}
<==> {{{x^2+4x - 12 >0}}}
<==> (x - 6)(x + 2) > 0
Critical numbers are 6, -2.
Choose test numbers -3, 0, and 7.
For ({{{-infinity}}}, -2), (-3 - 6)(-3 + 2) = -9*-1 = 9 >0
For (-2, 6), (0-6)(0+2) = -6*2 = -12 < 0
For (-2, {{{infinity}}}), (7-6)(7+2) = 9 >0.

Therefore, the solution set is ({{{-infinity}}}, -2)U (6, {{{infinity}}}).