Question 394408
{{{(abs(3x-1))/(abs(1-3x))=(abs(3(3)-1))/(abs(1-3(3)))=(abs(9-1))/(abs(1-9))=(abs(8))/(abs(-8))=8/8=1}}}



So {{{(abs(3x-1))/(abs(1-3x))=1}}} when {{{x=3}}}



Note: It turns out that {{{(abs(3x-1))/(abs(1-3x))=1}}} for any value of x (except {{{x=1/3}}}) because {{{abs(3x-1)=abs(1-3x)}}} for every value of x.



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