Question 394307
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Hi
using substitution to solve
x=2y+2
2x+3y=11
substituting (2y+3) for x
2(2y+2) + 3y = 11
solving for y
4y + 4 + 3y = 11
     7y = 7
      y = 1 and 
      x = 4       | x = 2y + 2= 2*1+2 = 4
One solution (4,1)
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(4, 1,0.3),
graph( 300, 300, -6, 6, -6, 6,0, .5x-1, (-2/3)x + 11/3))}}}