Question 394279
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Hi
3x2 + 9x + 1 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-9 +- sqrt( 69))/(6) }}} 
x is {-0.1156, -2.8844}
finding vertex by completing square
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = 3(x^2 + 3) + 1
y = 3[(x+3/2)^2 - 9/4] + 1
y = 3(x + 3/2)^2 -23/4  Vertex is Pt(-3/2,-23/4)

{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, 1,0.3),
circle(-1.5, -23/4,0.3),
graph( 300, 300, -6, 6, -6, 6, 3x^2 + 9x + 1 ))}}}