Question 394167
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Hi
3x <= –4y – 4    |adding 4y to and subtracting 3x from both sides of inequality 4y  &#8804; -3x - 4
 y  &#8804; -(3/4)x - 1  |dividing both sides of inequality by 4

I. First graphing y =  -(3/4)x - 1  |slope m = -(3/4), y-intercept Pt(0,1)
Note: as y increases/decreases by 3, x value changes by 4 in the opposite direction
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, -1,0.3),
circle(4, -4,0.3),
circle(-4, 2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,-(3/4)x - 1 ))}}}
II Shading appropiately: down from and including the line
*[invoke plot_any_inequality "y <=-(3/4)x - 1", -10, 10, -8, 12, 300, 300]