Question 394236
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Hi
line that is perpindicular to the line y=3/2x+4 would have slope m = -(2/3)
Note: the standard slope-intercept form for an equation of a line is: y = mx + b
  where m is the slope and b the y-intercept.  
y = -(2/3)x + b     |using ordered pair Pt(1,5) to solve for b
5 = -2/3 + b
5 2/3 = b
y = -(2/3)x + 17/3 
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, 4,0.3),
circle(0, 17/3,0.3),
graph( 300, 300, -6, 6, -6, 6,0, 1.5x + 4,-(2/3)x + 17/3  ))}}}