Question 394201
(6- 11i) is a point in the complex plane. The real part, 6
is plotted on the horizontal axis, and the imaginary part, -11i,
is plotted on the vertical axis.
If you were to draw the axes, measure 6 units to the right and
11 units down (since it's negative), then you have plotted a point
in the 4th quadrant. 
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In order to express this in trig form, you need an amplitude 
and an angle
The angle is a positive angle that is 270 degrees (3 quadrants) +
the angle whose tangent is 6/11.
{{{6/11 = .5454}}}
tan^-1(.5454) = 28.61 degrees
270 + 28.61 = 298.61 degrees
The amplitude is {{{sqrt(6^2 + 11^2)}}}
{{{sqrt(36 + 121) = sqrt(157)}}}
{{{sqrt(157) = 12.53}}}
So this is a line 12.53 units from the origin at an angle of 298.61 degrees
in the + direction (counterclockwise)