Question 42871
a) From x^2 - 4x - 5 = 0, we have
(x - 5)(x + 1) = 0
x = 5 and x = -1
b) From x^2 - 4x - 5 = 0, we have
x^2 - 4x + 4 - 5 = 4 
(x + 2)^2 - 5 = 4
(x + 2)^2 = 9
x + 2 = ± 3
x = 2 ± 3
x = 5, -1
c) From x^2 - 4x - 5 = 0, we have
x = (4 ± sqrt(16+20)) / 2
x = (4 ± sqrt(36)) / 2
x = (4 ± 6) / 2
x = 5, -1