Question 42752
First you need to find the LCD of the fraction to do this you have to factor each of the fractions.
{{{(5x-2)/(x^2-5x-14) - (3)/(x^2+2x)}}} The second fraction you can factor an x out of each
{{{(5x-2)/(x^2-5x-14) - (3)/((x)(x+2))}}}  The other fraction can be factored (x-7)(x+2)
{{{(5x-2)/((x-7)(x+2)) - (3)/((x)(x+2))}}}  Now you can compare the two and find the LCD which is (x(x-7)(x+2))
{{{((5x-2)(x))/((x)(x-7)(x-2)) - (3(x-7))/((x)(x+2)(x-7))}}}  Now you can do the multiplication
{{{(5x^2-2x)/((x)(x-7)(x-2)) - (3x-21)/((x)(x+2)(x-7))}}}  Now you can combine the two fractions
{{{(5x^2-2x-3x+21)/((x)(x-2)(x-7))}}}  Now combine like terms
{{{(5x^2-5x+21)/((x)(x-2)(x-7))}}}  Now you need to factor the top to see if you can reduce the fraction 
Which it can't factor so that would be your answer.