Question 393818
Tracy leaves for work at 8am, traveling at 36mph.
 Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch.
 At what time will Sarah catch Tracy?
:
Change 5 min to hr: 5/60 = .0833 hrs
:
Let t = Sarah's travel time
then
(t+.0833) = Tracey's travel time
:
When S catches T they will have traveled the same distance
Write a distance equation: d = speed * time
:
50t = 36(t+.0833)
50t = 36t + 3
50t - 36t = 3
14t = 3
t = {{{3/14}}} hrs is Sarah's travel time
Change to minutes {{{3/14}}}*60 = 12.85 min say 13 min
then
13 + 5 = 18 min is Tracy's travel time who left at 8:00
S catches T at about 8:18
:
:
We can check this finding the distance each traveled, should be equal
50*{{{13/60}}} = 10.8 mi
36*{{{18/60}}} = 10.8 mi