<PRE><B>Question 393935</B>
Find three consecutive integers such that 3 times the largest integer is 21 less than 5 times the middle interger. 
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1st: x-1
2nd: x
3rd: x+1
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Equation:
3(x+1)= 5x-21
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3x+3 = 5x-21
2x = 24
x = 12
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1st: x-1 = 11
2nd: x = 12
3rd: x+1 = 13
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Cheers,
Stan H.</PRE>