Question 393918
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4800(0.75)^t\ \leq\ 500]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (0.75)^t\ \leq\ \frac{5}{48}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln(0.75)^t\ \leq\ \ln(5)\ -\ \ln(48)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ln(0.75)\ \leq\ \ln(5)\ -\ \ln(48)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ \geq\ \frac{\ln(5)\ -\ \ln(48)}{\ln(0.75)}]


Note change of inequality sense because *[tex \Large \ln(0.75)\ <\ 0]


Calculate the RHS and round up to the next higher integer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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