Question 393917
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ v_ot\ +\ h_o]


where *[tex \Large h(t)] is the height in feet afte *[tex \Large t] elapsed seconds, *[tex \Large v_o] is the initial velocity in feet per second, and *[tex \Large h_o] is the initial height.


Plug in your values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ -16t^2\ +\ 16t\ +\ 96]


Since the water is at height = 0, set the function equal to zero and solve for the postive value of *[tex \Large t].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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