Question 393906
go about solving 343-7(x+3) if x+3 is raised to the second power?
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You have to have an equation to have a solution.
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343-7(x+3)^2 = 0
-7(x+3)^2 = -343
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(x+3)^2 - 49 = 0
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Factor:
(x+3-7)(x+3+7) = 0
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(x-4)(x+10) = 0
x = 4 or x = -10
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Cheers,
Stan H.