Question 393742
Find the value(s) of k for which the equation (x+2)(x+k)=-1 has equal roots.
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x^2+(k+2)x+2k = -1
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Has equal roots when the discriminant equals zero.
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(k+2)^2 -4*(2k) = 0
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k^2+4k+4-8k = 0
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k^2-4k+4 = 0
(k-2)^2 = 0
k = 2
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Cheers,
Stan H.