Question 393671
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Hi
Note: median of 15 units bisects the hypotenuse into two equal lengths of 15
that is: the distance  along the hyp from the alt to the short side = 6
 15 - sqrt(15^ - 12^) = 6
the length of the shorter leg is 6sqrt(5) in simplest radical form
 12^2 + 6^2 = sqrt(180) = 6sqrt(5)