Question 393594
3n, 3(n+1), 3(n+2), and 3(n+3)

Then
5(3n + 3(n+3)) = 13(3(n+2)) - 6
==> 5(3n + 3n + 9) = 39(n+2) - 6
==> 5(6n + 9) = 39n + 78 - 6
==> 30n+ 45 = 39n + 72
==> -27 = 9n
==> n = -3

Then the numbers are -9, -6, -3, 0.