Question 393550
{{{ -0.2x^2+12x+11 }}}
...
solve by quadratic formula
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
a=-0.2,b=12,c=11
b^2-4ac=152.8
{{{x1=(-(12)+sqrt(152.8))/(-0.4)}}}
x1=-0.90
{{{x2=(-(12)-sqrt(152.8))/-0.4}}}
x2=60.90
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