<PRE><B>Question 393540</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;Volume of a box=length*width*height &lt;br&gt;

We can easily see that the height of the box will be x.&lt;br&gt;

What about the length and the width?&lt;br&gt;

The length should be 10 inches minus x inches minus x inches, since there would be two x&#39;s cut out of the length.&lt;br&gt;

The width should be 6 inches minus x inches minus x inches, since there would be two x&#39;s cut out of the width as well.&lt;br&gt;

So, we have:&lt;br&gt;

height=x&lt;br&gt;

length=10-2x&lt;br&gt;

width=6-2x&lt;br&gt;

{{{Volume=x*(10-2x)*(6-2x)}}} inches cubed&lt;br&gt;

{{{V=4x^3-32x^2+60x}}} inches cubed&lt;br&gt;

You can multiply those terms out using the FOIL method and you will end up with the correct answer.&lt;br&gt;

In some cases, it might be easier to leave the Volume in that first factored form.&lt;br&gt;

I hope this helps!&lt;br&gt;</PRE>