Question 393475
Car One leaves on time and travels at 50 mph. Car Two leaves one hour later and travels at 75 mph. For how long does each car travel before the second car catches up to the first?
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First car DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
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Second car DATA:
rate = 75 mph ; time = x-1 hrs ; distance = rt = 75(x-1) miles
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Equation: 
distance = distance
50x = 75(x-1)
50x = 75x-75
-25x = -75
x = 3 hrs (1st car time)
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x-1 = 2 hrs (2nd car time)
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cheers,
Stan H.